eifueo/docs/1b/math119.md

248 lines
8.7 KiB
Markdown
Raw Normal View History

2023-01-09 08:23:07 -05:00
# MATH 119: Calculus 2
2023-01-10 11:38:11 -05:00
## Multivariable functions
2023-01-10 13:39:19 -05:00
!!! definition
- A **multivariable function** accepts more than one independent variable, e.g., $f(x, y)$.
The signature of multivariable functions is indicated in the form *[identifier]*: *[input type]**[return type]*. Where $n$ is the number of inputs:
$$f: \mathbb R^n \to \mathbb R$$
!!! example
The following function is in the form $f: \mathbb R^2\to\mathbb R$ and maps two variables into one called $z$ via function $f$.
$$(x,y)\longmapsto z=f(x,y)$$
2023-01-10 11:38:11 -05:00
### Sketching multivariable functions
2023-01-10 13:39:19 -05:00
!!! definition
- In a **scalar field**, each point in space is assigned a number. For example, topography or altitude maps are scalar fields.
- A **level curve** is a slice of a three-dimensional graph by setting to a general variable $f(x, y)=k$. It is effectively a series of contour plots set in a three-dimensional plane.
- A **contour plot** is a graph obtained by substituting a constant for $k$ in a level curve.
2023-01-10 14:02:44 -05:00
Please see [level set](https://en.wikipedia.org/wiki/Level_set) and [contour line](https://en.wikipedia.org/wiki/Contour_line) for example images.
2023-01-10 13:39:19 -05:00
2023-01-10 16:04:33 -05:00
In order to create a sketch for a multivariable function, this site does not have enough pictures so you should watch a YouTube video.
!!! example
For the function $z=x^2+y^2$:
For each $x, y, z$:
- Set $k$ equal to the variable and substitute it into the equation
- Sketch a two-dimensional graph with constant values of $k$ (e.g., $k=-2, -1, 0, 1, 2$) using the other two variables as axes
Combine the three **contour plots** in a three-dimensional plane to form the full sketch.
2023-01-11 15:39:46 -05:00
A **hyperbola** is formed when the difference between two points is constant. Where $r$ is the x-intercept:
$$x^2-y^2=r^2$$
<img src="/resources/images/hyperbola.svg" width=600 />
If $r^2$ is negative, the hyperbola is is bounded by functions of $x$, instead.
## Limits of two-variable functions
A function is continuous at $(x, y)$ if and only if all possible lines through $(x, y)$ have the same limit. Or, where $L$ is a constant:
$$\text{continuous}\iff \lim_{(x, y)\to(x_0, y_0)}f(x, y) = L$$
In practice, this means that if any two paths result in different limits, the limit is undefined. Substituting $x|y=0$ or $y=mx$ or $x=my$ are common solutions.
!!! example
For the function $\lim_{(x, y)\to (0,0)}\frac{x^2}{x^2+y^2}$:
Along $y=0$:
2023-01-15 17:14:01 -05:00
$$\lim_{(x,0)\to(0, 0)} ... = 1$$
2023-01-11 15:39:46 -05:00
Along $x=0$:
$$\lim_{(0, y)\to(0, 0)} ... = 0$$
Therefore the limit does not exist.
2023-01-15 17:32:31 -05:00
## Partial derivatives
Partial derivatives have multiple different symbols that all mean the same thing:
$$\frac{\partial f}{\partial x}=\partial_x f=f_x$$
For two-input-variable equations, setting one of the input variables to a constant will return the derivative of the slice at that constant.
By definition, the **partial** derivative of $f$ with respect to $x$ (in the x-direction) at point $(a, B)$ is:
$$\frac{\partial f}{\partial x}(a, B)=\lim_{h\to 0}\frac{f(a+h, B)-f(a, B)}{h}$$
Effectively:
- if finding $f_x$, $y$ should be treated as constant.
- if finding $f_y$, $x$ should be treated as constant.
!!! example
With the function $f(x,y)=x^2\sqrt{y}+\cos\pi y$:
\begin{align*}
f_x(1,1)&=\lim_{h\to 0}\frac{f(1+h,1)-f(1,1)} h \\
\tag*{$f(1,1)=1+\cos\pi=0$}&=\lim_{h\to 0}\frac{(1+h)^2-1} h \\
&=\lim_{h\to 0}\frac{h^2+2h} h \\
&= 2 \\
\end{align*}
### Higher order derivatives
!!! definition
- **wrt.** is short for "with respect to".
$$\frac{\partial^2f}{\partial x^2}=\partial_{xx}f=f_{xx}$$
Derivatives of different variables can be combined:
$$f_{xy}=\frac{\partial}{\partial y}\frac{\partial f}{\partial x}=\frac{\partial^2 f}{\partial xy}$$
The order of the variables matter: $f_{xy}$ is the derivative of f wrt. x *and then* wrt. y.
**Clairaut's theorem** states that if $f_x, f_y$, and $f_{xy}$ all exist near $(a, b)$ and $f_{yx}$ is continuous **at** $(a,b)$, $f_{yx}(a,b)=f_{x,y}(a,b)$ and exists.
!!! warning
In multivariable calculus, **differentiability does not imply continuity**.
2023-01-16 21:39:40 -05:00
### Linear approximations
A **tangent plane** represents all possible partial derivatives at a point of a function.
For two-dimensional functions, the differential could be used to extrapolate points ahead or behind a point on a curve.
$$
\Delta f=f'(a)\Delta d \\
\boxed{y=f(a)+f'(a)(x-a)}
$$
The equations of the two unit direction vectors in $x$ and $y$ can be used to find the normal of the tangent plane:
$$
\vec n=\vec d_1\times\vec d_2 \\
\begin{bmatrix}-f_x(a,b) \\ -f_y(a,b) \\ 1\end{bmatrix} = \begin{bmatrix}1\\0\\f_x(a,b)\end{bmatrix}
\begin{bmatrix}0\\1\\f_y(a,b)\end{bmatrix}
$$
Therefore, the general expression of a plane is equivalent to:
$$
z=C+A(x-a)+B(x-b) \\
\boxed{z=f(a,b)+f_x(a,b)(x-a)+f_y(a,b)(y-b)}
$$
??? tip "Proof"
The general formula for a plane is $c_1(x-a)+c_2(y-b)+c_3(z-c)=0$.
If $y$ is constant such that $y=b$:
$$z=C+A(x-a)$$
which must represent in the x-direction as an equation in the form $y=b+mx$. It follows that $A=f_x(a,b)$. A similar concept exists for $f_y(a,b)$.
If both $x=a$ and $y=b$ are constant:
$$z=C$$
where $C$ must be the $z$-point.
Usually, functions can be approximated via the **tangent at $x=a$.**
$$f(x)\simeq L(x)$$
!!! warning
Approximations are less accurate the stronger the curve and the farther the point is away from $f(a,b)$. A greater $|f''(a)|$ indicates a stronger curve.
!!! example
Given the function $f(x,y)=\ln(\sqrt[3]{x}+\sqrt[4]{y}-1)$, $f(1.03, 0.98)$ can be linearly approximated.
$$
L(x=1.03, y=0.98)=f(1,1)=f_x(1,1)(x-1)+f_y(1,1)(y-1) \\
f(1.03,0.98)\simeq L(1.03,0.98)=0.005
$$
### Differentials
Linear approximations can be used with the help of differentials. Please see [MATH 117#Differentials](/1a/math117/#differentials) for more information.
$\Delta f$ can be assumed to be equivalent to $df$.
$$\Delta f=f_x(a,b)\Delta x+f_y(a,b)\Delta y$$
Alternatively, it can be expanded in Leibniz notation in the form of a **total differential**:
$$df=\frac{\partial f}{\partial x}dx+\frac{\partial f}{\partial y}dy$$
??? tip "Proof"
The general formula for a plane in three dimensions can be expressed as a tangent plane if the differential is small enough:
$$f(x,y)=f(a,b)+f_x(a,b)(x-a)+f_y(a,b)(x-b)$$
As $\Delta f=f(x,y)-f(a,b)$, $\Delta x=x-a$, and $\Delta y=y-b$, it can be assumed that $\Delta x=dx,\Delta y=dy, \Delta f\simeq df$.
$$\boxed{\Delta f\simeq df=f_x(a,b)dx+f_y(a,b)dy}$$
### Related rates
Please see [SL Math - Analysis and Approaches 1](/g11/mhf4u7/#related-rates) for more information.
!!! example
For the gas law $pV=nRT$, if $T$ increases by 1% and $V$ increases by 3%:
\begin{align*}
pV&=nRT \\
\ln p&=\ln nR + \ln T - \ln V \\
\tag{multiply both sides by $d$}\frac{d}{dp}\ln p(dp)&=0 + \frac{d}{dT}\ln T(dt)-\frac{d}{dV}\ln V(dV) \\
\frac{dp}{p} &=\frac{dT}{T}-\frac{dV}{V} \\
&=0.01-0.03 \\
&=-2\%
\end{align*}
### Parametric curves
Because of the existence of the parameter $t$, these expressions have some advantages over scalar equations:
- the direction of $x$ and $y$ can be determined as $t$ increases, and
- the rate of change of $x$ and $y$ relative to $t$ as well as each other is clearer
$$
\begin{align*}
f(x,y,z)&=\begin{bmatrix}x(t) \\ y(t) \\ z(t)\end{bmatrix} \\
&=(x(t), y(t), z(t))
\end{align*}
$$
2023-01-23 11:10:23 -05:00
The **derivative** of a parametric function is equal to the vector sum of the derivative of its components:
$$\frac{df}{dt}=\sqrt{\left(\frac{dx}{dt}\right)^2+\left(\frac{dy}{dt}\right)^2+\left(\frac{dz}{dt}\right)^2}$$
Sometimes, the **chain rule for multivariable functions** creates a new branch in a tree for each independent variable.
For two-variable functions, if $z=f(x,y)$:
$$\frac{dz}{dt}=\frac{\partial z}{\partial x}\frac{dx}{dt}+\frac{\partial z}{\partial y}\frac{dy}{dt}$$
Sample tree diagram:
<img src="/resources/images/two-var-tree.jpg" width=300>(Source: LibreTexts)</img>
!!! example
This can be extended for multiple functions — for the function $z=f(x,y)$, where $x=g(u,v)$ and $y=h(u,v)$:
<img src="/resources/images/many-var-tree.jpg" width=300>(Source: LibreTexts)</img>
Determining the partial derivatives with respect to $u$ or $v$ can be done by only following the branches that end with those terms.
$$
\frac{\partial z}{\partial u} = \frac{\partial z}{\partial x}\frac{\partial x}{\partial u} + \frac{\partial z}{\partial y}\frac{\partial y}{\partial u} \\
$$
!!! warning
If the function only depends on one variable, $\frac{d}{dx}$ is used. Multivariable functions must use $\frac{\partial}{\partial x}$ to treat the other variables as constant.
2023-01-23 20:45:03 -05:00