ece105: add angular momentum and torque
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@ -91,7 +91,7 @@ $$I=\int^M_0 R^2 dm$$
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- Hoop about diameter: $I=\frac{1}{2}MR^2$
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- Rod about center: $I=\frac{1}{12}ML^2$
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- Rod about end: $I=\frac{1}{3}ML^2$
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- Square slab about perpendicular axis through center: $I=\frac{1}{3}ML^2$
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- Thin rectangular plate about perpendicular axis through center: $I=\frac{1}{3}ML^2$
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### Rotational-translational equivalence
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@ -107,7 +107,7 @@ Angular velocity is related to velocity:
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$$\omega = \frac{v}{r}$$
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The direction of the tangential values can be determined via the right hand rule.
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The direction of the tangential values can be determined via the right hand rule. Where $r$ is the vector from the **origin to the mass**:
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$$
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\vec v = r\times\omega \\
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@ -124,3 +124,32 @@ And all kinematic equations have their rotational equivalents.
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Most translational equations also have rotational equivalents.
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$$E_\text{k rot} = \frac{1}{2}I\omega^2$$
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## Torque
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Torque is the rotational equivalent of force.
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$$\vec\tau=I\vec\alpha$$
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$$\vec\tau=\vec r\times\vec F$$
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$$|\vec\tau=|r||F|\sin\theta$$
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In the general case, especially when the force is variable, the work done is equal to the integral of force over displacement.
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$$W=\int^{x_f}_{x_i}F_xdx$$
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Work is also related to torque:
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$$W=\tau\Delta\theta$$
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$$W=F\Delta S$$
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The total net work from torque from external forces is equivalent to:
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$$W=\Delta E_k = \int^{\theta_f}_{\theta_i}\taud\theta$$
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### Angular momentum
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This is the same as linear momentum.
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$$\vec L = \vec r\times\vec p$$
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$$\vec L = I\vec\omega$$
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$$\vec L =\vec\tau t$$
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