ece105: add angular momentum and torque

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eggy 2022-11-13 15:30:04 -05:00
parent 6ba4ef1294
commit 08191a395a

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@ -91,7 +91,7 @@ $$I=\int^M_0 R^2 dm$$
- Hoop about diameter: $I=\frac{1}{2}MR^2$
- Rod about center: $I=\frac{1}{12}ML^2$
- Rod about end: $I=\frac{1}{3}ML^2$
- Square slab about perpendicular axis through center: $I=\frac{1}{3}ML^2$
- Thin rectangular plate about perpendicular axis through center: $I=\frac{1}{3}ML^2$
### Rotational-translational equivalence
@ -107,7 +107,7 @@ Angular velocity is related to velocity:
$$\omega = \frac{v}{r}$$
The direction of the tangential values can be determined via the right hand rule.
The direction of the tangential values can be determined via the right hand rule. Where $r$ is the vector from the **origin to the mass**:
$$
\vec v = r\times\omega \\
@ -124,3 +124,32 @@ And all kinematic equations have their rotational equivalents.
Most translational equations also have rotational equivalents.
$$E_\text{k rot} = \frac{1}{2}I\omega^2$$
## Torque
Torque is the rotational equivalent of force.
$$\vec\tau=I\vec\alpha$$
$$\vec\tau=\vec r\times\vec F$$
$$|\vec\tau=|r||F|\sin\theta$$
In the general case, especially when the force is variable, the work done is equal to the integral of force over displacement.
$$W=\int^{x_f}_{x_i}F_xdx$$
Work is also related to torque:
$$W=\tau\Delta\theta$$
$$W=F\Delta S$$
The total net work from torque from external forces is equivalent to:
$$W=\Delta E_k = \int^{\theta_f}_{\theta_i}\taud\theta$$
### Angular momentum
This is the same as linear momentum.
$$\vec L = \vec r\times\vec p$$
$$\vec L = I\vec\omega$$
$$\vec L =\vec\tau t$$