chem: Add Le Chatelier's principle
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| Change | $-y$ | $-y$ | $+2y$ |
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| Change | $-y$ | $-y$ | $+2y$ |
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| Equilibrium | 0.11 | 0.50$-y$ | $+2y$ |
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| Equilibrium | 0.11 | 0.50$-y$ | $+2y$ |
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### Le Chatelier's principle
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Le Chatelier's principle states that: If there is a change in a system at equilibrium, the position of equilibrium will readjust to minimise the effect of the change.
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The changes that this principle affects — and therefore affect equilibrium — include changes in temperature, concentration, and pressure. These changes are assumed to occur instantaneously, which may result in sudden theoretical spikes in concentration-time graphs.
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The initial rate of the change will start **fast** and then slow down, appearing as a sharp change instead into a curve in a concentration-time/reaction progress graph that **never return to its original value**.
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!!! tip
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Drawing horizontal dotted lines that represent the original position of equilibrium and vertical lines to represent the moment of system change makes it clearer to read.
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Increasing the **temperature** of a system causes it to shift in favour of the **endothermic** side, and vice versa.
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Of the three changes, this is the only one that would change $K_c$ as it changes the rate constants, which are temperature-specific ($K_c\propto\frac{r_\text{reverse}}{r_\text{forward}}$). Therefore, as temperature **increases**, $K_c$ also **increases**, and vice versa.
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!!! example
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If heat is added to a solution of KCl, more KCl will dissolve to minimise the change in temperature as it is an endothermic process.
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Increasing the **concentration** of a reactant or product will cause the position to shift **away** from the increased side, and vice versa.
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??? example
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If there is an **instantaneous** spike of $\ce{N2}$ to a system at equilibrium, it will be consumed along with $\ce{H2}$ to form $\ce{NH3}$, **but not enough to return to its original value**.
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<img src="/resources/images/equilibrium-concentration.png" width=500>(Source: Kognity)</img>
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The same applies if instead $\ce{NH3}$ is reduced.
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<img src="/resources/images/equilibrium-concentration-2.png" width=500>(Source: Kognity)</img>
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Increasing the **pressure** of a gas will cause the position to shift in whatever direction would **decrease** the total moles of gas.
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!!! warning
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Inert (uninvolved in a reaction) gases such as catalysts will not affect the position of equilibrium as it does not affect the **partial pressure** of the gas. In a similar vein, adding water to an aqueous solution will not cause any changes in equilibrium position.
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!!! warning
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If given a system not at equilibrium, if a change is made that would change the prior equilibrium, it should be assumed that the system reaches equilibrium before the change is made, regardless if it is specified.
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## Organic chemistry
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## Organic chemistry
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!!! definition
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!!! definition
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