math119: add related rates and differentials
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@ -165,3 +165,54 @@ $$f(x)\simeq L(x)$$
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L(x=1.03, y=0.98)=f(1,1)=f_x(1,1)(x-1)+f_y(1,1)(y-1) \\
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f(1.03,0.98)\simeq L(1.03,0.98)=0.005
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$$
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### Differentials
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Linear approximations can be used with the help of differentials. Please see [MATH 117#Differentials](/1a/math117/#differentials) for more information.
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$\Delta f$ can be assumed to be equivalent to $df$.
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$$\Delta f=f_x(a,b)\Delta x+f_y(a,b)\Delta y$$
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Alternatively, it can be expanded in Leibniz notation in the form of a **total differential**:
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$$df=\frac{\partial f}{\partial x}dx+\frac{\partial f}{\partial y}dy$$
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??? tip "Proof"
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The general formula for a plane in three dimensions can be expressed as a tangent plane if the differential is small enough:
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$$f(x,y)=f(a,b)+f_x(a,b)(x-a)+f_y(a,b)(x-b)$$
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As $\Delta f=f(x,y)-f(a,b)$, $\Delta x=x-a$, and $\Delta y=y-b$, it can be assumed that $\Delta x=dx,\Delta y=dy, \Delta f\simeq df$.
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$$\boxed{\Delta f\simeq df=f_x(a,b)dx+f_y(a,b)dy}$$
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### Related rates
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Please see [SL Math - Analysis and Approaches 1](/g11/mhf4u7/#related-rates) for more information.
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!!! example
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For the gas law $pV=nRT$, if $T$ increases by 1% and $V$ increases by 3%:
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\begin{align*}
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pV&=nRT \\
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\ln p&=\ln nR + \ln T - \ln V \\
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\tag{multiply both sides by $d$}\frac{d}{dp}\ln p(dp)&=0 + \frac{d}{dT}\ln T(dt)-\frac{d}{dV}\ln V(dV) \\
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\frac{dp}{p} &=\frac{dT}{T}-\frac{dV}{V} \\
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&=0.01-0.03 \\
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&=-2\%
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\end{align*}
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### Parametric curves
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Because of the existence of the parameter $t$, these expressions have some advantages over scalar equations:
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- the direction of $x$ and $y$ can be determined as $t$ increases, and
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- the rate of change of $x$ and $y$ relative to $t$ as well as each other is clearer
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$$
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\begin{align*}
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f(x,y,z)&=\begin{bmatrix}x(t) \\ y(t) \\ z(t)\end{bmatrix} \\
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&=(x(t), y(t), z(t))
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\end{align*}
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$$
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