math119: start triple integrals

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eggy 2023-02-17 11:05:06 -05:00
parent c7b3f211ea
commit 219377b4e6

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@ -561,3 +561,31 @@ $$\iint_R f(x,y)dA$$
&=\frac 2 3u^{3/2}du\biggr|^1_0 \\
&=\frac 2 3\pi
\end{align*}
## Triple integration
Much like double integrals:
The **volume** within bounds $E$ is the integral of 1:
$$V=\iiint_E1dV$$
The **average value** within a volume is:
$$\overline f_E=\frac 1 V\iiint_Ef(x,y,z)dV$$
!!! example
For the volume within $x+y+z=1$ and $2x+2y+z=2,x,y,z\geq 0$:
The points intersect the axes and each other to create the bounds $0\leq x\leq 1,0\leq y\leq 1-x,1-x-y\leq z\leq 2-2x-2y$.
$$\int^1_0\int^{1-x}_0\int^{2-2x-2y}_{1-x-y}1dz\ dy\ dx =\frac 1 6$$
The average value is:
$$6\iiint_Ez\ dV=\frac 3 4$$
The **total quantity** if $f$ represents density is:
$$T=\iiint_Ef(x,y,z)dV$$