math: add vector equations for straight lines

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eggy 2021-04-28 12:33:25 -04:00
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@ -396,6 +396,55 @@ Much like regular multiplication, dot products are:
When working with algebraic vectors, their dot products are equal to the products of their components. When working with algebraic vectors, their dot products are equal to the products of their components.
$$\vec{u}\bullet\vec{v}=u_xv_x+u_yv_y$$ $$\vec{u}\bullet\vec{v}=u_xv_x+u_yv_y$$
### Vector equations in two dimensions
!!! definition
The **Cartesian** form of a line is of the form $Ax+By+C$.
The vector equation for a straight line solves for an unknown position vector $\vec{r}$ on the line using a known position vector $\vec{r_0}$ on the line, a direction vector parallel to the line $\vec{m}$, and the variable **parameter** $t$. It is roughly similar to $y=b+xm$.
$$\vec{r}=\vec{r_0}+t\vec{m},t\in\mathbb{R}$$
The equation can be rewritten in the algebraic form to be
$$[x,y]=[x_0,y_0]+t[m_1,m_2], t\in\mathbb{R}$$
The direction vector is effectively the slope of a line.
$$m=[\Delta x, \Delta y]$$
To determine if a point lies along a line defined by a vector equation, the parameter $t$ should be checked to be the same for the $x$ and $y$ coordinates of the point.
!!! warning
Vector equations are **not unique** — there can be different position vectors and direction vectors that return the same line.
The **parametric** form of a line breaks the vector form into components.
$$
\begin{align*}
x&=x_0+tm_1 \\
y&=y_0+tm_2,t\in\mathbb{R}
\end{align*}
$$
The **symmetric** form of the equation takes the parametric form and equates the two equations to each other using $t$.
$$\frac{x-x_0}{m_1}=\frac{y-y_0}{m_2},m_1,m_2\neq 0$$
If one of the **direction numbers** $m_1$ or $m_2$ is zero, the equation is rearranged such that only one position component is on one side.
!!! example
Where $m_2=0$:
$$\frac{x-x_0}{m_1},y=y_0$$
### Vector equations in three dimensions
There is little difference between vector equations in two or three dimensions. An additional variable is added for the third dimension.
The vector form:
$$\vec{r}=\vec{r_0}+t\vec{m},t\in\mathbb{R}$$
The parametric form:
$$[x,y,z]=[x_0,y_0,z_0]+t[m_1,m_2,m_3],t\in\mathbb{R}$$
The symmetric form:
$$\frac{x-x_0}{m_1}=\frac{y-y_0}{m_2}=\frac{z-z_0}{m_3}$$
## Resources ## Resources
- [IB Math Analysis and Approaches Syllabus](/resources/g11/ib-math-syllabus.pdf) - [IB Math Analysis and Approaches Syllabus](/resources/g11/ib-math-syllabus.pdf)