ece105: add rolling motion

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eggy 2022-11-17 22:16:08 -05:00
parent 89328dcc56
commit 45f135f955

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@ -153,3 +153,44 @@ This is the same as linear momentum.
$$\vec L = \vec r\times\vec p$$ $$\vec L = \vec r\times\vec p$$
$$\vec L = I\vec\omega$$ $$\vec L = I\vec\omega$$
$$\vec L =\vec\tau t$$ $$\vec L =\vec\tau t$$
## Rolling motion
!!! definition
- **Slipping** is spinning without sliding.
- **Skidding** is sliding without spinning.
Pure rolling motion is **only true if** the tangential velocity of the centre of mass is equal to its rotational velocity.
$$v_{cm}=R\omega$$
In pure rolling motion, the point at the top is moving at two times the velocity while the point at the bottom has no tangential velocity.
<img src="https://upload.wikimedia.org/wikipedia/commons/8/8d/Velocitats_Roda.svg" width=500>(Source: Wikimedia Commons)</img>
For any point in the mass:
$$
v_{net} = v_{trans} + v_{rot} \\
v_{net} = v_{cm} + \vec R \times\vec\omega \\
E_{k roll} = E_{k trans} + E_{k rot}
$$
Alternatively, the rolling can be considered as a rotation about the pivot point between the disk and the ground, allowing rolling motion to be represented as rotational motion around the pivot point. The **parallel axis theorem** can be used to return it back to the original point.
$$\sum\tau_b=I_b\alpha$$
At least one external torque and one external force is required to initiate pure rolling motion because the two components are separate.
If an object is purely rolling and then it moves to:
- a flat, frictionless surface, it continues purely rolling
- an inclined, frictionless surface, external torque is needed to maintain pure rolling motion
- an inclined surface with friction, it continues purely rolling
Where $c$ is the coefficient to the moment of inertia ($I=cMR^2$), while rolling down an incline:
$$
v_{cm} = \sqrt{\frac{2}{1+c}gh} \\
a_{cm} = \frac{g\sin\theta}{1+c}
$$