math115: fix eigen def
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@ -943,8 +943,8 @@ $$(A-\lambda I)\vec x=\vec 0$$
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The determinant of the system can be used to check if there will be any eigenvectors.
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The determinant of the system can be used to check if there will be any eigenvectors.
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- If $\det(A-\lambda I)=0$, there is exactly one solution which is the trivial solution, so $\lambda$ is **not an eigenvalue**.
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- If $\det(A-\lambda I)=0$, there is exactly one solution which is the trivial solution, so $\lambda$ is **an eigenvalue**.
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- If $\det(A-\lambda I)\neq 0$, there are multiple solutions, so $\lambda$ is an eigenvalue.
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- If $\det(A-\lambda I)\neq 0$, there are multiple solutions, so $\lambda$ is **not** an eigenvalue.
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The **characteristic polynomial** of an eigenvalue is equal to its determinant, and can be used to solve for eigenvalues when $\lambda$ is unknown.
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The **characteristic polynomial** of an eigenvalue is equal to its determinant, and can be used to solve for eigenvalues when $\lambda$ is unknown.
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