math119: add limits

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eggy 2023-01-11 15:39:46 -05:00
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@ -34,3 +34,33 @@ In order to create a sketch for a multivariable function, this site does not hav
- Sketch a two-dimensional graph with constant values of $k$ (e.g., $k=-2, -1, 0, 1, 2$) using the other two variables as axes - Sketch a two-dimensional graph with constant values of $k$ (e.g., $k=-2, -1, 0, 1, 2$) using the other two variables as axes
Combine the three **contour plots** in a three-dimensional plane to form the full sketch. Combine the three **contour plots** in a three-dimensional plane to form the full sketch.
A **hyperbola** is formed when the difference between two points is constant. Where $r$ is the x-intercept:
$$x^2-y^2=r^2$$
<img src="/resources/images/hyperbola.svg" width=600 />
If $r^2$ is negative, the hyperbola is is bounded by functions of $x$, instead.
## Limits of two-variable functions
A function is continuous at $(x, y)$ if and only if all possible lines through $(x, y)$ have the same limit. Or, where $L$ is a constant:
$$\text{continuous}\iff \lim_{(x, y)\to(x_0, y_0)}f(x, y) = L$$
In practice, this means that if any two paths result in different limits, the limit is undefined. Substituting $x|y=0$ or $y=mx$ or $x=my$ are common solutions.
!!! example
For the function $\lim_{(x, y)\to (0,0)}\frac{x^2}{x^2+y^2}$:
Along $y=0$:
$$\lim_{(x,0)\to(0, 0) ... = 1$$
Along $x=0$:
$$\lim_{(0, y)\to(0, 0)} ... = 0$$
Therefore the limit does not exist.