eggy/eifueo
1
1
Fork 1
Code Issues 2 Pull Requests Releases Wiki Activity

ece140: guess thevinin

Browse Source
This commit is contained in:
eggy 2023-02-07 11:16:26 -05:00
parent e610ada836
commit 7b99e1ccf5
1 changed files with 19 additions and 0 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

19
docs/1b/ece140.md
View File

@ -168,3 +168,22 @@ In linear circuits, a voltage source in series with a resistor can be replaced b
$$v_1=i_2R$$
The arrow of the current source must point in the positive direction of the voltage source. This can also be used with dependent sources.
### Thevenin's theorem
Any part of a circuit including an independent source can be replaced with exactly one voltage source and a resistor in series. Two circuits are **Thevenin equivalent** if their $\lambda$ are equal in $V=\lambda I$.
1. Cut off the load.
2. Group the rest of the circuit together, removing all independent sources (short / open).
3. The Thevenin resistance of the new resistor is the same as the load $R_{Th}=R_L$.
If dependent sources exist, the load should be replaced with an independent source of arbitrary value (e.g., 1 V) and the other variable determined to find $R_{Th}=V_{Th}/I$, where $V_{Th}$ is the voltage drop across the load.
Across the load:
$$
I_L=\frac{V_{Th}}{R_{Th}+R_L} \\
V_L=R_LI_L = \frac{R_L}{R_{Th}+R_L}V_{Th}
!!! warning
A negative resistance $R_{L}$ indicates that the load supplies power.