math: add vector line intersections

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eggy 2021-04-28 15:17:13 -04:00
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@ -396,10 +396,10 @@ Much like regular multiplication, dot products are:
When working with algebraic vectors, their dot products are equal to the products of their components.
$$\vec{u}\bullet\vec{v}=u_xv_x+u_yv_y$$
### Vector equations in two dimensions
### Vector line equations in two dimensions
!!! definition
The **Cartesian** form of a line is of the form $Ax+By+C$.
The **Cartesian** or **scalar** form of a line is of the form $Ax+By+C$.
The vector equation for a straight line solves for an unknown position vector $\vec{r}$ on the line using a known position vector $\vec{r_0}$ on the line, a direction vector parallel to the line $\vec{m}$, and the variable **parameter** $t$. It is roughly similar to $y=b+xm$.
$$\vec{r}=\vec{r_0}+t\vec{m},t\in\mathbb{R}$$
@ -408,7 +408,10 @@ The equation can be rewritten in the algebraic form to be
$$[x,y]=[x_0,y_0]+t[m_1,m_2], t\in\mathbb{R}$$
The direction vector is effectively the slope of a line.
$$m=[\Delta x, \Delta y]$$
$$\vec{m}=[\Delta x, \Delta y]$$
For a line in scalar form:
$$\vec{m}=[B, -A]$$
To determine if a point lies along a line defined by a vector equation, the parameter $t$ should be checked to be the same for the $x$ and $y$ coordinates of the point.
@ -432,7 +435,7 @@ If one of the **direction numbers** $m_1$ or $m_2$ is zero, the equation is rear
Where $m_2=0$:
$$\frac{x-x_0}{m_1},y=y_0$$
### Vector equations in three dimensions
### Vector line equations in three dimensions
There is little difference between vector equations in two or three dimensions. An additional variable is added for the third dimension.
@ -445,6 +448,17 @@ $$[x,y,z]=[x_0,y_0,z_0]+t[m_1,m_2,m_3],t\in\mathbb{R}$$
The symmetric form:
$$\frac{x-x_0}{m_1}=\frac{y-y_0}{m_2}=\frac{z-z_0}{m_3}$$
### Intersections of vector equation lines
Two lines are parallel if their direction vectors are scalar multiples of each other.
$$\vec{m_1}=k\vec{m_2},k\in\mathbb{R}$$
Two lines are coincident if they are parallel and share at least one point. Otherwise, they are distinct.
If two lines are not parallel and in two dimensions, they intersect. To solve for the point of intersection, the x and y variables in the parametric form can be equated and the parameter $t$ solved.
In three dimensions, there is a final possibility should the lines not be parallel: the lines may be *skew*. To determine if the lines are skew, the x, y, and z variables of **two** parametric equations should be equated to their counterparts in the other vector as if they intersect. The resulting $t$ and $s$ from the first and second line respectively should be substituted into the third equation and an equality check performed. Should there not be a solution that fulfills the third equation, the lines are skew. Otherwise, they intersect.
## Resources
- [IB Math Analysis and Approaches Syllabus](/resources/g11/ib-math-syllabus.pdf)