phys: add black bodies

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eggy 2021-03-28 17:17:16 -04:00
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@ -437,6 +437,46 @@ Instead of converting between multiple forms of energy, solar heating directly c
<img src="/resources/images/solar-heating.png" width=700>(Source: Kognity)</img>
## Thermal energy transfer
!!! definition
- **Radiation** is the transfer of energy via electromagnetic waves emitted away from an object. No medium is needed.
- **Convection** is the transfer of thermal energy via another medium away from an object.
- **Conduction** is the transfer of thermal energy via physical contact.
### Black bodies
!!! definition
**Emissivity** ($e$) is a dimensionless value from 0 to 1 indicating the relative ability of an object to emit radiation. Darker and duller surfaces have an emissivity closer to 1 while shinier and whiter ones are closer to 0.
All bodies with an absolute temperature will emit radiant energy in the form of electromagnetic waves. The temperature of the body determines the wavelengths and power of the radiation emitted. A **perfect emitter** has an emissivity of 1 and is known as a **black body**, absorbing all electromagnetic radiation.
Generally, as the temperature of a body goes down, its peak power density is reduced and its peak wavelength increases.
**Wien's displacement law** relates the temperature of a black body to the waves it emits. Where $\lambda_\text{max}$ is the peak wavelength in metres and $T$ is the temperature of the body in kelvin:
$$\lambda_\text{max}\times T=\pu{2.9\times10^{-3} m\cdot K}$$
The **Stefan-Boltzmann** law relates the specifications of a body to the power it emits. Where $P$ is the power emitted by the body, $A$ is its surface area, $T$ is its temperature, $e$ is its emissivity, and $\sigma$ is the Stefan-Boltzmann constant (equal to $\pu{5.67\times10^{-8} Wm^{-2}K^{-4}}$):
$$P=e\sigma AT^4$$
In problems where the environment temperature is **different** from the temperature of an object, there will be power loss. The net power emitted by a body will be:
$$P_\text{net}=e\sigma A(T_1^4-T_2^4)$$
The solar radiation reaching earth is equal to $\pu{S=3.9\times10^{26} W}$ with the assumption that it is a black body.
### Albedo
Derived from $I=\frac{P}{A}$, where $d$ is the distance from the Earth to the sun:
$$I=\frac{P}{4\pi d^2}$$
**Albedo** ($\alpha$) is the ratio of power from incident rays reflected or scattered to the power absorbed by a body, ranging from 0 to 1. A black body has albedo 0. On average, Earth's albedo is equal to $0.3$ due primarily to the atmosphere but also clouds and ice.
$$\alpha=\frac{\text{energy scattered/reflected}}{\text{energy absorbed}}$$
As Earth is not a flat disk pointed at the sun, in reality the sun's intensity is reduced arbitrarily to a quarter. Therefore, the power absorbed/incident to the Earth is equal to, where $S$ is the solar constant:
$$P_\text{in}=(1-\alpha)\frac{1}{4}SA$$
Greenhouse gases are responsible for remaining increases in temperature.
## Resources
- [IB Physics Data Booklet](/resources/g11/ib-physics-data-booklet.pdf)