math: Add plane intersections
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@ -602,6 +602,19 @@ $$d=\frac{|Ax_1+By_1+Cz_1+D|}{\sqrt{A^2+B^2+C^2}}$$
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The shortest distance between two parallel planes is equal to:
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The shortest distance between two parallel planes is equal to:
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$$d=\frac{|D_1-D_2|}{\sqrt{A^2+B^2+C^2}}$$
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$$d=\frac{|D_1-D_2|}{\sqrt{A^2+B^2+C^2}}$$
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Two planes are parallel if their direction vectors are scalar multiples of each other:
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$$\vec n_1 = k\vec n_2$$
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If they are also coincident, the D-values will also be identical:
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$$D_1=D_2$$
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Otherwise, the planes intersect, the line along which is equal to the cross product between the two direction vectors.
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$$\vec m=\vec n_1\times\vec n_2$$
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An initial point vector can be solved by setting any of the variables ($x,y,z$) to zero and solving for the others. Alternatively, the parameter $t$ can be set equal to one of the variables instead and the parametric equation derived that way.
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The **angle between two planes** is equal to the angle between their normal direction vectors, which can be determined using the dot product formula.
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## Resources
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## Resources
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- [IB Math Analysis and Approaches Syllabus](/resources/g11/ib-math-syllabus.pdf)
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- [IB Math Analysis and Approaches Syllabus](/resources/g11/ib-math-syllabus.pdf)
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