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phys: fix pu MeV

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eggy 2021-03-16 13:44:37 -04:00
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@ -109,7 +109,7 @@ A higher **binding energy per nucleon** results in more energy required to break
<img src="/resources/images/binding-energy-curve.png" width=700>(Source: Kognity)</img> <img src="/resources/images/binding-energy-curve.png" width=700>(Source: Kognity)</img>
!!! note !!! note
It is required to know the general shape of the curve, that $\pu{~8.8 MeV}$ is the maximum, and that the end boundaries are $0$ and $\pu{~7.5 MeV}$. It is also required to know the elements at each of those points (hydrogen-1, iron-56/nickel-62, and uranium-238). It is required to know the general shape of the curve, that $~8.8 \pu{ MeV}$ is the maximum, and that the end boundaries are $0$ and $~7.5 \pu{ MeV}$. It is also required to know the elements at each of those points (hydrogen-1, iron-56/nickel-62, and uranium-238).
Since a greater binding energy per nucleon is more energetically favourable, nuclei to the right of iron-56 fission (split) while those to the left fuse (combine) to release energy — changes that would increase binding energy per nucleon are likely to occur because of this. Since a greater binding energy per nucleon is more energetically favourable, nuclei to the right of iron-56 fission (split) while those to the left fuse (combine) to release energy — changes that would increase binding energy per nucleon are likely to occur because of this.