# SL Math - Analysis and Approaches - 2 The course code for this page is **MCV4U7**. ## Integration Integration is an operation that finds the **net** area under a curve, and is the opposite operation of differentiation. As such, it is also known as **anti-differentiation**. The area under a curve between the interval of x-values $[a,b]$ is: $$A=\lim_{x\to\infty}\sum^n_{i=1}f(x_i)\Delta x$$ which can be simplified to, where $dx$ indicates that integration should be performed with respect to $x$: $$A=\int^b_a f(x)dx$$ While $\Sigma$ refers to a finite sum, $\int$ refers to the sum of a limit. As integration is the opposite operation of differentiation, they can cancel each other out. $$\frac{d}{dx}\int f(x)dx=f(x)$$ The **integral** or **anti-derivative** of a function is capitalised by convention. Where $C$ is an unknown constant: $$\int f(x)dx=F(x)+C$$ When integrating, there is always an unknown constant $C$ as there are infinitely many possible functions that have the same rate of change but have different vertical translations. !!! definition - $C$ is known as the **constant of integration**. - $f(x)$ is the **integrand**. ### Integration rules $$ \begin{align*} &\int 1dx &= &&x+C \\ &\int (ax^n)dx, n≠-1 &=&&\frac{a}{n+1}x^{n+1} + C \\ &\int (x^{-1})dx&=&&\ln|x|+C \\ &\int (ax+b)^{-1}dx&=&&\frac{\ln|ax+b|}{a}+C \\ &\int (ae^{kx})dx &= &&\frac{a}{k}e^{kx} + C \\ &\int (\sin kx)dx &= &&\frac{-\cos kx}{k}+C \\ &\int (\cos kx)dx &= &&\frac{\sin kx}{k}+C \\ \end{align*} $$ Similar to differentiation, integration allows for constant multiples to be brought out and terms to be considered individually. $$ \begin{align*} &\int k\cdot f(x)dx&=&&k\int f(x)dx \\ &\int[f(x)\pm g(x)]dx&=&&\int f(x)dx \pm \int g(x)dx \end{align*} $$ ### Indefinite integration The indefinite integral of a function contains every possible anti-derivative — that is, it contains the constant of integration $C$. $$\int f(x)dx=F(x)+C$$ ### Substitution rule Similar to limit evaluation, the substitution of complex expressions involving $x$ and $dx$ with $u$ and $du$ is generally used to work with the chain rule. $$ u=g(x) \\ \int f(g(x))\cdot g´(x)\cdot dx = \int f(u)\cdot du $$ ??? example To solve $\int (x\sqrt{x-1})dx$: $$ let\ u=x-1 \\ ∴ \frac{du}{dx}=1 \\ ∴ du=dx \\ \begin{align*} \int (x\sqrt{x-1})dx &\to \int(u+1)(u^\frac{1}{2})du \\ &= \int(u^\frac{3}{2}+u^\frac{1}{2})du \\ &= \frac{2}{5}u^\frac{5}{2}+\frac{2}{3}u^\frac{3}{2}+C \\ &= \frac{2}{5}(x-1)^\frac{5}{2} + \frac{2}{3}(x-1)^\frac{3}{2} + C \end{align*} $$ ### Definite integration To find a numerical value of the area under the curve in the bounded interval $[a,b]$, the **definite** integral can be taken. $$\int^b_a f(x)dx$$ $a$ and $b$ are known as the lower and upper **limits of integration**, respectively. (Source; Kognity) Regions **under** the x-axis are treated as negative while those above are positive, cancelling each other out, so the definite integral finds something like the net area over an interval. If $f(x)$ is continuous at $[a,b]$ and $F(x)$ is the anti-derivative, the definite integral is equal to: $$\int^b_a f(x)dx=F(x)\biggr]^b_a=F(b)-F(a)$$ As such, it can be evaluated manually by integrating the function and subtracting the two anti-derivatives. !!! warning If $u$-substitution is used, the limits of integration must be adjusted accordingly. To find the total **area** enclosed between the x-axis, $x=a$, $x=b$, and $f(x)$, the function needs to be split at each x-intercept and the absolute value of each definite integral in those intervals summed. $$A=\int^b_a \big|f(x)\big| dx$$ ### Properties of definite integration The following rules only apply while $f(x)$ and $g(x)$ are continuous in the interval $[a,b]$ and $c$ is a constant. $$ \begin{align*} &\int^a_a f(x)dx&=&&0 \\ &\int^b_a c\cdot dx&=&&c(b-a) \\ &\int^b_a f(x)dx&=&&-\int^b_a f(x)dx \\ &\int^c_a f(x)dx&=&&\int^b_a f(x)dx + \int^c_b f(x)dx \end{align*} $$ The **constant multiple** and **sum** rules still apply. ## Resources - [IB Math Analysis and Approaches Syllabus](/resources/g11/ib-math-syllabus.pdf) - [IB Math Analysis and Approaches Formula Booklet](/resources/g11/ib-math-data-booklet.pdf) - [Textbook: Calculus and Vectors 12](/resources/g11/calculus-vectors-textbook.pdf) - [Textbook: Oxford SL Mathematics](/resources/g11/textbook-oxford-math.pdf) - [Course Pack Unit 1: Integration](/resources/g11/s2cp1.pdf) - [TI-84 Plus Calculator Guide](/resources/g11/ti-84-plus.pdf)