- Follow order of operation, inorder to do know which operation to do first.
- Example: Given $`(2+4) \times 5 - 9 \div 3`$
- First do everything in brackets: $`(6) \times 5 - 9 \div 3`$
- Then do multiplication/division: $`30 - 3`$
- Then finally, do subtaction/addition: $`27`$
- The answer is `27`.
## Fractions / Rational Numbers
- The number on the top is called the `numerator`.
- The number on the bottom is called the `denominator`.
- A fraction in its most simple form is when the `numerator` and `denominator` cannot be both divided by the same number.
### Additions / Subtractions With Fractions
- Example: $`\frac{3}{5} + \frac{4}{3}`$
- Find `common denominator`, which is `15`, as `5` and `3` both are factors of `15`.
- You can do this easily with a table, just count by the number you are using, for example:
- |Counting by 5s | Counting by 3s |
|:--|:--|
|5|3|
|10|6|
|15|9|
|20|12|
|25|15|
- As you can see, both columns contain the number `15`, so `15` is the common denominator.
- Now, after we find the denominator, we must convert the fraction so that it has the `common denominator`. To do this, we must multiply the denominator by a number, so that it equals the `common denominator`. For the first fracion $`\frac{3}{5}`$, the `denominator` is `5`, to get to `15`, we must multiply it by `3`. Now, whatever we do on the bottom, me **MUST** do it on the top too, so we also multiply the `numerator` by `3` as well, the new fraction is now $`\frac{3 \times 3}{5 \times 3} = \frac{9}{15}`$.
- We now do the same thing to the other fraction: $`\frac{4 \times 5}{3 \times 5} = \frac{20}{15}`$
- Now that the denominators are the same and the fractions are converted, we can just simply add the `numerators` together while keeping the `denominator` the same. The result is $`\frac{9 + 20}{15} = \frac{29}{15}`$.
- The same steps applied to subtracion, with the only difference of subtacting the numerators rather than adding them.
### Multiplaction With Fractions
- To multiply a fracion, simply multiply the `numerators` together, and the `denominators` together.