If given a function in the form $`y = af[k(x-d)] + c`$, then let $`(x,y)`$ be the original points, the new points will be $`(\dfrac{1}{k}x+d, ay+c)`$.
The domain and range of the exponential function is:
- $`D : \{x | x \in \mathbb{R}\}`$
- $`R : \{y | y > 0, y \in \mathbb{R}\}`$
The domain and range of the logarithmic function is
- $`D: \{x | x > 0, x \in \mathbb{R}\}`$
- $`R: \{y | y \in \mathbb{R}\}`$
If $`f(x)`$ is a function, then the inverse is $`f^{-1}(x)`$. The inverse has the following properties:
- Domain of $`f(x)`$ = Range of $`f^{-1}(x)`$
- Range of $`f(x)`$ = Domain of $`f^{-1}(x)`$
Graphically, the inverse of a function is by reflecting the original function over the line $`y=x`$.
A vertical line test is used to test whether a relation is a function. If any 2 points can be drawn through a vertical line, then that relation is **not a function**.
To solve/find the inverse of a function, just swap the $`y`$ and $`x`$ and isolate/solve for $`y`$.
## Exponential Decay/Growth
When the base ($`b`$) is in the range $`0 \lt b \lt 1`$, the exponential funciton is said to have a **exponential decay**, the smaller the base, the stronger the decay.
When the base ($`b`$) is in the range $`b \gt 1`$, the exponential function is said to have a **exponential growth**, the bigger the base, the stronger the growth.
## Graphing Exponential Functions
If you have **exponential growth** (meaning your base is greater than $`1`$), use more positive values rather than negative values.
If you have **exponential decay** (meaning your base is in the range $`(0, 1)`$), use more negative values rather than positive values.
**Don't forget the asymtote.**
## Logarithmic Function
The logarithmic function is the **inverse** of the exponential function.
In essence, if $`x = b^y`$, then $`\log_b x = y`$
**Note:** The logarithm is defined only for $`b > 0, b \ne 1`$
**Note 2:** The symbol $`ln`$ is $`log_e`$, we usually call it the **natural log**.
## Logrithm Laws
1. $`\log_b(b^x) = x`$
2. $`b^{\log_b(x)} = x`$
3. $`\log_b(1) = 0`$
4. $`\log_b(b) = 1`$
|Law|Form|Example|
|:--|:---|:------|
|Change Of Base (COB)|$`\log_a(b) = \dfrac{\log_m(b)}{\log_m(a)}`$|$`\log_2(5) = \dfrac{\log_{10}(5)}{\log_{10}(2)}`$|
|Change Of Base (COB)|$`\log_a(b) = \dfrac{1}{\log_b(a)}`$|$`\log_2(5) = \dfrac{1}{\log_5(2)}`$|