From 50e7bd45e8e7d85341703a6e9a86908ad52ecc81 Mon Sep 17 00:00:00 2001 From: James Su Date: Thu, 18 Apr 2019 16:25:34 +0000 Subject: [PATCH] Update Final_Exam_Study_Sheet.md --- Grade 9/Math/MPM1DZ/Final_Exam_Study_Sheet.md | 29 +++++++++++-------- 1 file changed, 17 insertions(+), 12 deletions(-) diff --git a/Grade 9/Math/MPM1DZ/Final_Exam_Study_Sheet.md b/Grade 9/Math/MPM1DZ/Final_Exam_Study_Sheet.md index 0e936a1..14a0c1b 100644 --- a/Grade 9/Math/MPM1DZ/Final_Exam_Study_Sheet.md +++ b/Grade 9/Math/MPM1DZ/Final_Exam_Study_Sheet.md @@ -194,12 +194,12 @@ |Type|Example| |:--:|:-----:| - |Perfect Square Trinomials| (a+b)2 = a2+2ab+b2 or (a-b)2 = a2-2ab+b| - |Difference with Squares|a2-b2 = (a+b)(a-b)| - |Simple Trinomials|x2+6x-7 = (x+7)(x-1)| - |Complex Trinomials|2x2-21x-11 = (2x+1)(x-11)| - |Common Factor|2ab+6b+4 = 2(ab+3b+2)| - |Factor By Grouping|ax+ay+bx+by = (ax+ay)+(bx+by) = a(x+y)+b(x+y) = (a+b)(x+y)| + |Perfect Square Trinomials| $`(a+b)^2 = a^2+2ab+b^2 or (a-b)^2 = a^2-2ab+b^2`$| + |Difference with Squares|$`a^2-b^2 = (a+b)(a-b)`$| + |Simple Trinomials|$`x^2+6x-7 = (x+7)(x-1)`$| + |Complex Trinomials|$`2x^2-21x-11 = (2x+1)(x-11)`$| + |Common Factor|$`2ab+6b+4 = 2(ab+3b+2)`$| + |Factor By Grouping|$`ax+ay+bx+by = (ax+ay)+(bx+by) = a(x+y)+b(x+y) = (a+b)(x+y)`$| ## Shortcuts @@ -235,9 +235,14 @@ - equations will have the absolute bracket be positive while the other negative. - Absolute values are written in the form ```| x |``` - where - - if x > 0, | x | = x - - if x = 0, | x | = 0 - - if x < 0, | x | = -x +$` +| x | = +\begin{cases} +x, & \text{if } x > 0\\ +0, & \text{if } x = 0\\ +-x, & \text{if } x < 0 +\end{cases} +`$ ## Quadractic Equations - ```Quadratic Function```: A parabolic graph where the axis of symmetry is parallel to the y-axis @@ -245,11 +250,11 @@ - Solve quadratic equation by: 1. Isolation - - a(x+b)2 + k = 0 + - $`a(x+b)^2 + k = 0`$ 2. Factor using zero-product property - ```The Zero Factor Property``` refers to when a×b=0, then either a=0 or b=0. - - (x-a)(x-b)=0 - - x = a, b + - $`(x-a)(x-b)=0`$ + - $`x = a, b`$ -