diff --git a/Grade 10/Math/MPM2DZ/Math Oral Presentation Questions/Unit 1: Analytical Geometry.md b/Grade 10/Math/MPM2DZ/Math Oral Presentation Questions/Unit 1: Analytical Geometry.md
index 02a0c27..0c45a25 100644
--- a/Grade 10/Math/MPM2DZ/Math Oral Presentation Questions/Unit 1: Analytical Geometry.md	
+++ b/Grade 10/Math/MPM2DZ/Math Oral Presentation Questions/Unit 1: Analytical Geometry.md	
@@ -77,7 +77,7 @@ midpoint = $` (\dfrac{\sqrt{72} + \sqrt{32}}{2}, \dfrac{-\sqrt{12} - \sqrt{48}}{
 
 $` = ( \dfrac{6\sqrt{2} + 4\sqrt{2}}{2}, \dfrac{-2\sqrt{3}, -4\sqrt{3}}{2}) `$
 
-$` = 3\sqrt{2} + 2\sqrt{2}, -\sqrt{3 - 2\sqrt{3}`$
+$` = 3\sqrt{2} + 2\sqrt{2}, -\sqrt{3} - 2\sqrt{3}`$
 
 $` = (5\sqrt{2}, -3\sqrt{3})`$
 
@@ -197,7 +197,7 @@ Let $`(x, y)`$ be the center of the circle, and $`r`$ be the radius of the circl
 
 Sub $`(1)`$ into $`(2)`$
 
-$`x^2 + 8x + 16 + y^2 - 16y + 64 = x^2 - 10x + 25 + y^2 -2y + 1`$
+$`x^2 - 8x + 16 + y^2 - 16y + 64 = x^2 - 10x + 25 + y^2 -2y + 1`$
 
 $`-8x -16y + 80 = -10x - 2y + 26`$