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Update Unit 2: Quadratic Equations 2.md
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@ -32,11 +32,10 @@ When $`h = 0`$, the ball hits ground, so:
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$`-3.2t^2 + 12.8 + 1 = 0`$
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$`t = \dfrac{12.8 \pm \sqrt{151.04}}{6.4}`$
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$`t = \dfrac{12.8 \pm \sqrt{176.64}}{6.4}`$
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$`\because t \ge 0`$
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$`\therefore t = \dfrac{12.8 \pm \sqrt{176.64}}{6.4}`$
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$`\therefore t \approx 4.1`$
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