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Update Unit 2: Quadratic Equations 2.md

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James Su 2020-01-13 15:08:25 +00:00
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@ -32,11 +32,10 @@ When $`h = 0`$, the ball hits ground, so:
$`-3.2t^2 + 12.8 + 1 = 0`$
$`t = \dfrac{12.8 \pm \sqrt{151.04}}{6.4}`$
$`t = \dfrac{12.8 \pm \sqrt{176.64}}{6.4}`$
$`\because t \ge 0`$
$`\therefore t = \dfrac{12.8 \pm \sqrt{176.64}}{6.4}`$
$`\therefore t \approx 4.1`$