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Update Trig Quiz 1.md

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James Su 2019-11-14 14:53:59 +00:00
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@ -102,7 +102,7 @@ $`\cos(\beta) = \dfrac{AF}{AE} = \dfrac{AF}{1} = AF`$
$`\text{Draw a parallel line to } CD \text{ that connects point } E \text{ to } AD. \quad \cos(\alpha + \beta) = \dfrac{BE}{AE} = \dfrac{BE}{1} = BE`$ $`\text{Draw a parallel line to } CD \text{ that connects point } E \text{ to } AD. \quad \cos(\alpha + \beta) = \dfrac{BE}{AE} = \dfrac{BE}{1} = BE`$
$`\therefore \sin(\alpha + \beta) = CD = CF + FD = \cos(\alpha) \sin(\beta) + \sin(\alpha) + \cos(\beta)`$ $`\therefore \sin(\alpha + \beta) = CD = CF + FD = \cos(\alpha) \sin(\beta) + \sin(\alpha) \cos(\beta)`$
$`\therefore \cos(\alpha + \beta) = BE = \cos(\alpha - \beta)`$ $`\therefore \cos(\alpha + \beta) = BE = \cos(\alpha - \beta)`$
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