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Update Unit 2: Quadratic Equations 2.md

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James Su 2020-01-13 15:00:50 +00:00
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@ -36,11 +36,11 @@ $`t = \dfrac{12.8 \pm \sqrt{151.04}}{6.4}`$
$`\because t \ge 0`$
$`\therefore t = \dfrac{12.8 \pm \sqrt{151.04}}{6.4}`$
$`\therefore t = \dfrac{12.8 \pm \sqrt{176.64}}{6.4}`$
$`\therefore t \approx 3.9`$
$`\therefore t \approx 4.1`$
The ball will strike the ground at approximately $`3.9`$ seconds.
The ball will strike the ground at approximately $`4.1`$ seconds.
### Question 5 a)