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Update Unit 2: Quadratic Equations 2.md
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@ -36,11 +36,11 @@ $`t = \dfrac{12.8 \pm \sqrt{151.04}}{6.4}`$
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$`\because t \ge 0`$
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$`\therefore t = \dfrac{12.8 \pm \sqrt{151.04}}{6.4}`$
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$`\therefore t = \dfrac{12.8 \pm \sqrt{176.64}}{6.4}`$
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$`\therefore t \approx 3.9`$
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$`\therefore t \approx 4.1`$
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The ball will strike the ground at approximately $`3.9`$ seconds.
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The ball will strike the ground at approximately $`4.1`$ seconds.
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### Question 5 a)
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