From c3d28f2e0d524e0158c58488fb98a37ff1cc54e2 Mon Sep 17 00:00:00 2001 From: James Su Date: Mon, 14 Sep 2020 17:41:18 +0000 Subject: [PATCH] Update Unit 3: Trigonometric Equations.md --- Grade 10/Math/MCR3U7/Unit 3: Trigonometric Equations.md | 3 ++- 1 file changed, 2 insertions(+), 1 deletion(-) diff --git a/Grade 10/Math/MCR3U7/Unit 3: Trigonometric Equations.md b/Grade 10/Math/MCR3U7/Unit 3: Trigonometric Equations.md index 2a23266..2c4e456 100644 --- a/Grade 10/Math/MCR3U7/Unit 3: Trigonometric Equations.md +++ b/Grade 10/Math/MCR3U7/Unit 3: Trigonometric Equations.md @@ -70,5 +70,6 @@ To find the area of a sector of a circle, the formula is as follows. $`\text{Sector Area } = (\text{Area of Circle})(\% \text{ Of Circle shaded in})`$ -$`A = (\pir^2)(\dfrac{\theta}{2\pi})`$ +$`A = (\pi r^2)(\dfrac{\theta}{2\pi})`$ + $`A = \dfrac{1}{2}\theta r^2`$