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Update Final_Exam_Study_Sheet.md

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James Su 2019-09-03 22:27:21 +00:00
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@ -362,7 +362,7 @@ x, & \text{if } x > 0\\
|Shape|Maximum Area|Minimum Perimeter|
|:----|:-----------|:----------------|
|4-sided rectangle|A rectangle must be a square to maximaze the area for a given perimeter. The length is equal to the width<br>$`A = lw`$<br>$`A_{max} = (w)(w)`$<br>$`A_{max} = w^2`$|A rectangle must be a square to minimaze the perimeter for a given area. The length is equal to the width.<br>$`P = 2(l+w)`$<br>$`P_{min} = 2(w)(w)`$<br>$`P_{min} = 2(2w)`$<br>$`P_{min} = 4w`$|
|4-sided rectangle|A rectangle must be a square to maximaze the area for a given perimeter. The length is equal to the width<br>$`A = lw`$<br>$`A_{max} = (w)(w)`$<br>$`A_{max} = w^2`$|A rectangle must be a square to minimaze the perimeter for a given area. The length is equal to the width.<br>$`P = 2(l+w)`$<br>$`P_{min} = 2(w + w)`$<br>$`P_{min} = 2(2w)`$<br>$`P_{min} = 4w`$|
|3-sided rectangle|$`l = 2w`$<br>$`A = lw`$<br>$`A_{max} = 2w(w)`$<br>$`A_{max} = 2w^2`$|$`l = 2w`$<br>$`P = l+2w`$<br>$`P_{min} = 2w+2w`$<br>$`P_{min} = 4w`$|