From 8fe2c6f86b89d23b87e5f5f4b4e888f7a58dfb1d Mon Sep 17 00:00:00 2001 From: eggy Date: Wed, 19 May 2021 15:48:58 -0400 Subject: [PATCH] math: Add component operations and rearrange vector headers --- docs/mcv4u7.md | 23 ++++++++++++++++------- 1 file changed, 16 insertions(+), 7 deletions(-) diff --git a/docs/mcv4u7.md b/docs/mcv4u7.md index c4b7a3c..bb73626 100644 --- a/docs/mcv4u7.md +++ b/docs/mcv4u7.md @@ -372,7 +372,7 @@ In general, the x-plane is the one in and out of the page, the y-plane left and ### Vector operations -Please see [SL Physics 1#Adding/subtracting vectors diagrammatically](/sph3u7/#addingsubtracting-vectors-diagrammatically) for more details. +Please see [SL Physics 1#Adding/subtracting vectors diagrammatically](/sph3u7/#addingsubtracting-vectors-diagrammatically) for more details. The sum of two vectors is known as the **resultant** while the negative (opposite direction) version of that vector is known as the **equilibrant**. The sum of two vectors can also be solved diagrammatically by envisioning the head-to-tail as a parallelogram. @@ -459,11 +459,6 @@ If two lines are not parallel and in two dimensions, they intersect. To solve fo In three dimensions, there is a final possibility should the lines not be parallel: the lines may be *skew*. To determine if the lines are skew, the x, y, and z variables of **two** parametric equations should be equated to their counterparts in the other vector as if they intersect. The resulting $t$ and $s$ from the first and second line respectively should be substituted into the third equation and an equality check performed. Should there not be a solution that fulfills the third equation, the lines are skew. Otherwise, they intersect. -### Applications of vector equations - -For an object moving at **constant velocity in 2D space**, where $\vec{s}$ is its displacement, $\vec{s}_0$ is its initial displacement at $t=0$, $t$ is the time elapsed, and $\vec{v}$ is its velocity: -$$\vec{s}=\vec{s}_0+t\vec{v}$$ - ### Vector projections If two vectors $\vec{a}$ and $\vec{b}$ are placed tail-to-tail, the **component** of $\vec{a}$ in the direction of $\vec{b}$ is known as the **vector projection of $\vec{a}$ onto $\vec{b}$**. Represented by $Projection$, its magnitude is called the **scalar projection**. @@ -527,7 +522,7 @@ To determine the **direction** of a cross product, the right-hand rule can be us - the index finger is the direction of the second vector - the palm faces the direction of the cross product -### Applications of dot and cross products +### Applications of vector operations A **triple scalar product** is the result of a cross product performed first then put in a dot product. $$|\vec{c}\bullet(\vec{a}\times\vec{b})|$$ @@ -535,6 +530,9 @@ $$|\vec{c}\bullet(\vec{a}\times\vec{b})|$$ In a **parallelpiped**, or a three-dimensional shape with six faces each a parallelogram with an identical one opposite it, the volume is the triple scalar product of the distinct three vectors that make up its side lengths: $$A=|\vec{c}\bullet(\vec{a}\times\vec{b})|$$ +For an object moving at **constant velocity in 2D space**, where $\vec{s}$ is its displacement, $\vec{s}_0$ is its initial displacement at $t=0$, $t$ is the time elapsed, and $\vec{v}$ is its velocity: +$$\vec{s}=\vec{s}_0+t\vec{v}$$ + **Torque** ($\vec{\tau}$ or $\vec{M}$) is the ability to rotate an object — effectively angular/rotational force — and is the cross product of the **outward-pointing radius vector** ($\vec{r}$) and the **force** vector ($\vec{F}$). $$ \begin{align*} @@ -547,6 +545,17 @@ $$ The direction of the torque can be found using the **right-hand rule**. +**Force** and **velocity** are vectors with magnitude and direction. See [SL Physics 1#Force diagrams](/sph3u7/#force-diagrams) and [SL Physics 1#Velocity](/sph3u7/#velocity) for more information. + +### Operations with vector components + +If **Cartesian vectors** (see [SL Physics 1#Adding/subtracting vectors algebraically](/sph3u7/addingsubtracting-vectors-algebraically) for more details) cannot be used, the **sine and cosine laws** can be used, which are, respectively: + +Where $a$, $b$, and $c$ are the lengths of a triangle, and $A$, $B$, and $C$ are their angles opposite to them: +$$\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}$$ + +$$c^2=a^2+b^2-2ab\cos C$$ + ## Resources - [IB Math Analysis and Approaches Syllabus](/resources/g11/ib-math-syllabus.pdf)