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phys: add kognity vector information
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@ -149,6 +149,68 @@ $$intercept_{best fit} ± intercept_{max} - intercept_{min}$$
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## 1.3 - Vectors and scalars
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## 1.3 - Vectors and scalars
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!!! note "Definition"
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- **Scalar:** A physical quantity with a numerical value and unit.
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- **Vector:** A physical quantity with a numerical value, unit, and **direction.**
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??? example
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- Physical quantities represented by scalars include speed, distance, mass, temperature, pressure, time, frequency, current, voltage, and more.
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- Physical quantities represented by vectors include velocity, displacement, acceleration, force (e.g., weight), momentum, impulse, and more.
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Vectors are represented as arrows whose length represents their scale/magnitude and their orientation refer to their direction.
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### Adding/subtracting vectors diagrammatically
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1. Draw the first vector.
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2. Draw the second vector with its *tail* at the *head* of the first vector.
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3. Repeat step 2 as necessary for as many vectors as you want by attaching them to the *head* of the last vector.
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4. Draw a new vector from the *tail* of the first vector to the *head* of the last vector.
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<img src="/resources/images/vector-add-direction.png" width=700>(Source: Kognity)</img>
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When subtracting a vector, **negate** the vector being subtracted by giving it an opposite direction.
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<img src="/resources/images/vector-subtract-direction.png" width=700>(Source: Kognity)</img>
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### Parallelogram rule
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The parallelogram rule states that the sum of two vectors that form two sides of a parallelogram is the diagonal of that parallelogram.
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<img src="/resources/images/vector-parallelogram.png" width=700>(Source: Kognity)</img>
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### Multiplying vectors and scalars
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The product of a vector multiplied by a scalar is a vector with a magnitude of the vector multiplied by the scalar with the same direction as the original vector.
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$$v[direction] × s = (v×s)[direction]$$
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### Vector decomposition
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By breaking up a vector into lengths along the x- and y-axes, the sum of two vectors can be calculated algebraically.
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<img src="/resources/images/vector-decomposition.png" width=700>(Source: Kognity)</img>
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For vector $\textbf{a}$ and vector $\textbf{b}$:
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$$
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a_{x} = a\cos\theta_{a} \\
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a_{y} = a\sin\theta_{a}
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$$
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Proof:
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$a=\sqrt{a^{2}_{x}+a^{2}_{y}} \\$
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$=\sqrt{(a\cos\theta_{a})^2 + (a\sin\theta{a})^2} \\$
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$=\sqrt{a^2(\cos\theta_{a}^2 + \sin\theta_{a}^2)} \\$
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$=\sqrt{a^2} \\$
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$=a$
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From the diagram above, we can figure out that:
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$$
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r_{magnitude}=\sqrt{(a\cos\theta_{a} + b\cos\theta_{b})^2 + (a\sin\theta_{a} + b\cos\theta_{b})^2} \\
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r_{direction}=\tan^{-1}(\frac{a\sin\theta_{a} + b\sin\theta_{b}}{a\cos\theta_{a} + b\cos\theta_{b}})
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$$
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## Resources
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## Resources
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- [IB Physics Data Booklet](/resources/g11/ib-physics-data-booklet.pdf)
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- [IB Physics Data Booklet](/resources/g11/ib-physics-data-booklet.pdf)
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