math119: add change of var

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eggy 2023-02-08 11:17:48 -05:00
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@ -432,3 +432,51 @@ $$dA=dxdy=\rho d\rho d\phi$$
In general, the radius should be the inner integral, and functions converted from Cartesian to polar forms. In general, the radius should be the inner integral, and functions converted from Cartesian to polar forms.
$$\int^{\phi_2}_{\phi_1}\int^{\rho_2}_{\rho_1}f(\rho\cos\phi,\rho\sin\phi)\rho d\rho d\phi$$ $$\int^{\phi_2}_{\phi_1}\int^{\rho_2}_{\rho_1}f(\rho\cos\phi,\rho\sin\phi)\rho d\rho d\phi$$
### Change of variables
The **Jacobian** is the proportion of change in the differentials between different coordinate systems.
$$
\frac{\partial(x,y)}{\partial(u, v)}=\det\begin{bmatrix}
\partial x / \partial u & \partial x / \partial v \\
\partial y / \partial u & \partial y / \partial v
\end{bmatrix}
$$
The Jacobian can be treated as a fraction — it may be easier to determine the reciprocal of the Jacobian and then reciprocal it again.
When converting between two systems, the absolute value of the Jacobian should be incorporated.
$$dA=\left|\frac{\partial(x,y)}{\partial(u,v)}\right|du\ dv$$
!!! example
The Jacobian of the polar coordinate system relative to the Cartesian coordinate system is $\rho$. Therefore, $dA=\rho\ d\rho\ d\phi$.
If $x=x(u,v)$, $y=y(u,v)$, and $\partial(x,y)/\partial(u,v)\neq 0$ in the domain of $u$ and $v$ $D_{uv}$:
$$\iint_{D_{xy}}f(x,y)dA = \iint_{D_{uv}}f(x(u,v),y(u,v))\left|\frac{\partial(x,y)}{\partial(u,v)}\right|du\ dv$$
1. Pick a good transformation that simplifies the domain and/or the function.
2. Compute the Jacobian
3. Determine bounds (domain)
4. Integrate with the formula
If the Jacobian contains $x$ and/or $y$ terms:
- they can be substituted into the integral directly, praying that the terms all cancel out
- or $x$ and $y$ can be written in terms of $u$ and $v$ and then all substituted
### Applications of multiple integrals
The area enclosed within bounds $R$ is the volume with a height of 1.
$$A_R=\iint_R 1\ dA$$
The average value of the function $f(x,y)$ over a region $R$, where $A_R$ is the area of the region:
$$\overline{f}_R=\frac{1}{A_R}\iint_Rf(x,y) dA$$
The total "amount" of within a region, if $f(x,y)$ describes the density at point $(x,y)$:
$$\iint_R f(x,y)dA$$