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phys: fix intensity formula

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eggy 2021-01-11 16:08:55 -05:00
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docs/sph3u7.md
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@ -699,7 +699,7 @@ $$E\propto I\propto A^2$$
$$E=E_0\cos\theta$$ $$E=E_0\cos\theta$$
And so: And so:
$$I=I_0\cos\theta$$ $$I=I_0\cos^2\theta$$
When **unpolarised light** passes through a polariser, the average result of $I\cos\theta$ is $\frac{1}{2}$, so the intensity of polarised light is **half** of the intensity of unpolarised light. When **unpolarised light** passes through a polariser, the average result of $I\cos\theta$ is $\frac{1}{2}$, so the intensity of polarised light is **half** of the intensity of unpolarised light.