phys: add kognity vector information

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eggy 2020-09-21 20:35:15 -04:00
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@ -149,6 +149,68 @@ $$intercept_{best fit} ± intercept_{max} - intercept_{min}$$
## 1.3 - Vectors and scalars
!!! note "Definition"
- **Scalar:** A physical quantity with a numerical value and unit.
- **Vector:** A physical quantity with a numerical value, unit, and **direction.**
??? example
- Physical quantities represented by scalars include speed, distance, mass, temperature, pressure, time, frequency, current, voltage, and more.
- Physical quantities represented by vectors include velocity, displacement, acceleration, force (e.g., weight), momentum, impulse, and more.
Vectors are represented as arrows whose length represents their scale/magnitude and their orientation refer to their direction.
### Adding/subtracting vectors diagrammatically
1. Draw the first vector.
2. Draw the second vector with its *tail* at the *head* of the first vector.
3. Repeat step 2 as necessary for as many vectors as you want by attaching them to the *head* of the last vector.
4. Draw a new vector from the *tail* of the first vector to the *head* of the last vector.
<img src="/resources/images/vector-add-direction.png" width=700>(Source: Kognity)</img>
When subtracting a vector, **negate** the vector being subtracted by giving it an opposite direction.
<img src="/resources/images/vector-subtract-direction.png" width=700>(Source: Kognity)</img>
### Parallelogram rule
The parallelogram rule states that the sum of two vectors that form two sides of a parallelogram is the diagonal of that parallelogram.
<img src="/resources/images/vector-parallelogram.png" width=700>(Source: Kognity)</img>
### Multiplying vectors and scalars
The product of a vector multiplied by a scalar is a vector with a magnitude of the vector multiplied by the scalar with the same direction as the original vector.
$$v[direction] × s = (v×s)[direction]$$
### Vector decomposition
By breaking up a vector into lengths along the x- and y-axes, the sum of two vectors can be calculated algebraically.
<img src="/resources/images/vector-decomposition.png" width=700>(Source: Kognity)</img>
For vector $\textbf{a}$ and vector $\textbf{b}$:
$$
a_{x} = a\cos\theta_{a} \\
a_{y} = a\sin\theta_{a}
$$
Proof:
$a=\sqrt{a^{2}_{x}+a^{2}_{y}} \\$
$=\sqrt{(a\cos\theta_{a})^2 + (a\sin\theta{a})^2} \\$
$=\sqrt{a^2(\cos\theta_{a}^2 + \sin\theta_{a}^2)} \\$
$=\sqrt{a^2} \\$
$=a$
From the diagram above, we can figure out that:
$$
r_{magnitude}=\sqrt{(a\cos\theta_{a} + b\cos\theta_{b})^2 + (a\sin\theta_{a} + b\cos\theta_{b})^2} \\
r_{direction}=\tan^{-1}(\frac{a\sin\theta_{a} + b\sin\theta_{b}}{a\cos\theta_{a} + b\cos\theta_{b}})
$$
## Resources
- [IB Physics Data Booklet](/resources/g11/ib-physics-data-booklet.pdf)