math117: add inte end part 1

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eggy 2022-11-13 15:47:33 -05:00
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@ -576,6 +576,8 @@ Please see [SL Math - Analysis and Approaches 2#Area between two curves](/g11/mc
- A **Type 2** region is bounded by functions of $y$, which can be solved by integrating $y$. - A **Type 2** region is bounded by functions of $y$, which can be solved by integrating $y$.
- A **Type 3** region can be viewed as either Type 1 or 2. - A **Type 3** region can be viewed as either Type 1 or 2.
Substituting $u=\cos\theta$, $du=-\sin\theta d\theta$ is common.
### Mean values ### Mean values
@ -596,3 +598,46 @@ If $a\in\mathbb R$, functions of the form $\sqrt{x^2\pm a^2}$ or $\sqrt{a^2-x^2}
- In $\sqrt{a^2-x^2} \rightarrow x=a\sin\theta$ - In $\sqrt{a^2-x^2} \rightarrow x=a\sin\theta$
…which can be used to derive other trig identities to be integrated. …which can be used to derive other trig identities to be integrated.
### Rational integrals
All integrals of rational functions are expressible as more rational functions, ln, and arctan.
Partial fraction decomposition is useful here.
$$\int \frac{1}{x^2+a^2}dx=\frac{1}{a}tan^{-1}\left(\frac{x}{a}\right)+C$$
## Summary of all integration rules
- $\int x^n\ dx = \frac{1}{n+1}x^{n+1} + C,n\neq -1$
- $\int \frac{1}{x}dx = \ln|x| + C$
- $\int e^x\ dx = e^x + C$
- $\int a^x\ dx = \frac{1}{\ln a} a^x + C$
- $\int\cos x\ dx = \sin x + C$
- $\int\sin x\ dx = -\cos x + C$
- $\int\sec^2 x\ dx = \tan x + C$
- $\int\csc^2 x\ dx = -\cot x + C$
- $\int\sec x\tan x\ dx = \sec x + C$
- $\int\csc x\cot x\ dx = -\csc x + C$
- $\int\text{cosh}\ x\ dx = \text{sinh}\ x + C$
- $\int\text{sinh}\ x\ dx = \text{cosh}\ x + C$
- $\int\text{sech}^2\ x\ dx = \text{tanh}\ x + C$
- $\int\text{sech}\ x\text{tanh}\ x\ dx = \text{sech}\ x + C$
- $\int\frac{1}{1+x^2}dx=\tan^{-1}x+C$
- $\int\frac{1}{a^2+x^2}dx=\frac{1}{a}\tan^{-1}\left(\frac{x}{a}\right)+C$
- $\int\frac{1}{\sqrt{1-x^2}}dx=\sin^{-1}x+C$
- $\int\frac{1}{x\sqrt{x^2-1}}dx=\sec^{-1}x+C$
- $\int\sec x\ dx = \ln|\sec x+\tan x|+C$
- $\int\csc x\ dx = -\ln|\csc x + \cot x|+C$
## Applications of integration
The length of a curve over a given interval is equal to:
$$L=\int^b_a\sqrt{1+\left(\frac{dy}{dx}\right)^2\ dx}$$
For curves bounded by functions of $y$:
$$L(y)=\int^b_a\sqrt{1+\left(\frac{dx}{dy}\right)^2\ dy}$$
### Solids of revolution