math119: add power series and big o

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eggy 2023-04-10 13:59:05 -04:00
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@ -790,4 +790,62 @@ An absolutely converging series also has its regular form converge.
A series converges **conditionally** if it converges but not absolutely. This indicates that it is possible for all $b\in\mathbb R$ to rearrange $\sum a_n$ to cause it to converge to $b$.
### Power series
A power series **centred at $x_0$** is an infinitely long polynomial.
$$\sum^\infty_{n=0}c_n(x-x_0)^n$$
If there are multiple identified domains of convergence, the endpoints must be tested separately to get the **interval of convergence**. The **radius of convergence** is the amplitude of the interval, regardless of inclusion/exclusion.
$$r=\frac{\text{max}-\text{min}}{2}$$
For a power series of radius $R$, regardless if it is differentiated, integrated, multiplied (by non-zero), the radius remains $R$.
!!! warning
The interval may change.
Adding functions with different radii results in a radius roughly near the smaller interval of convergence.
The **binomial series** is the infinite expansion of $(1+x)^m$ with radius 1.
$$(1+x)^m=\sum^\infty_{n=0}\frac{m(m-1)(m-2)...(m-n+1)}{n!}x^n$$
## Big O notation
A function $f$ is of order $g$ as $x\to x_0$ if $|f(x)|\leq c|g(x)|$ for all $x$ near $x_0$. This is written as big O:
$$f(x)=O(g(x))\text{ as }x\to x_0$$
The inner function only dictates how it grows, discarding any constant terms.
!!! example
As $x\to 0$, $x^3=O(x^2)$ as well as $O(x)$ and $O(1)$. Thus $kx^3=O(x^2)$ for all $k\in\mathbb R$.
However, $x^3=O(x^4)$ only as $x\to\infty$ by the definition.
!!! example
As $|\sin x|\leq |x|$, $\sin x=O(x)$ as $x\to 0$.
If $f=O(x^m)$ and $g=O(x^n)$ as $x\to 0$:
- $fg=O(x^{m+n})$
- $f+g=O(x^q)$, where `q=min(m,n)`
- $kO(x^n)=O(x^n)$
- $O(x^n)^m=O(x^{nm})$
- $O(x^m)\div x^n=O(x^{m-n})$
With Taylor series, big O is the remainder.
$$R_n(x)=O((x-x_0)^{n+1})$$
The limit of big O is the behaviour of $g(x)$.
!!! example
\begin{align*}
\lim_{x\to 0}\frac{x^2e^x+2\cos x-2}{x^3}&=\lim_{x\to 0}\frac{x^3+O(x^4)}{x^3} \\
&= 1+O(x) \\
&= 1
\end{align*}