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Update Unit 1: Analytical Geometry Part 1.md

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James Su 2020-01-13 00:53:39 +00:00
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commit 700d29c843
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Grade 10/Math/MPM2DZ/Math Oral Presentation Questions/Unit 1: Analytical Geometry Part 1.md
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@ -22,7 +22,7 @@ $`m_{AB} = \dfrac{2-5}{7-(-1)} = \dfrac{-3}{8}`$
$`m_{\perp AB} = \dfrac{8}{3}`$
$`y_{\perp AB} - (-4) = \dfrac{8}{3}(x - (-1)) \implies y_{perp AB} + 4 = \dfrac{8}{3}(x+1)`$
$`y_{\perp AB} - (-4) = \dfrac{8}{3}(x - (-1)) \implies y_{\perp AB} + 4 = \dfrac{8}{3}(x+1)`$
$`y_{\perp AB} = \dfrac{8}{3}x + \dfrac{8}{3} - 4`$
@ -87,7 +87,7 @@ $`\therefore`$ The midpoint is at $`(5 \sqrt{2}, -3\sqrt{3})`$
Center of mass = centroid.
Centroid = where all median lines of a trinagle intersect.
Centroid = where all median lines of a triangle intersect.
$`M_{AB} = (\dfrac{8+12}{2}, \dfrac{12+4}{2}) = (10, 8)`$