Update Unit 3: Trigonometric Equations.md

Grade 10/Math/MCR3U7/Unit 3: Trigonometric Equations.md

@@ -6,4 +6,69 @@ Some special ratios you should know:
 
 $`\csc \theta = \dfrac{1}{sin \theta}`$
 
-$`\sec \theta = \dfrac{1}{\cos \theta}`$
+$`\sec \theta = \dfrac{1}{\cos \theta}`$
+
+$`\cot \theta = \dfrac{1}{\tan \theta}`$
+
+## Special Angles
+
+These are the angles in trigonometery that have "nice" solutions, and does not require a calculator.
+
+|Degrees|$`0^o`$|$`30^o`$|$`45^o`$|$`60^o`$|$`90^o`$|
+|:------|:------|:-------|:-------|:-------|:-------|
+|$`\sin \theta`$|$`0`$|$`\dfrac{1}{2}`$|$`\dfrac{\sqrt{2}}{2}`$|$`\dfrac{\sqrt{3}}{2}`$|$`1`$|
+|$`\cos \theta`$|$`1`$|$`\dfrac{\sqrt{3}}{2}`$|$`\dfrac{\sqrt{2}}{2}`$|$`\dfrac{1}{2}`$|$`0`$|
+|$`\tan \theta`$|$`0`$|$`\dfrac{1}{sqrt{3}}`$|$`1`$|$`\sqrt{3}`$| UNDEFINED|
+
+## Standard Position and Co-terminal Angles
+
+`Standard position` consists of 2 arms and an angle. The arm that is **ALWAYS** on the x-axis is called the `initial arm`. And the other arm is called the `terminal arm`.
+
+Positive angles go counter-clockwise direction (to the right), and negative angles go clockwise direction (to the left).
+
+`Co-terminal Angles` are angles whose terminal arms have the same standard position. Any 2 angles that are $`360^o`$ apart are considered `Co-terminal angles`.
+
+## The CAST Rule
+
+`Principal Angle` $`\theta`$: This is the angle usually given in the question. It is the counter-clockwise angle bewteen the initial arm and the terminal arm of an angle in standard position.
+
+`Related Acute Angle or Reference Angle` ($`\alpha`$): The angle between the terminal arm and the **x-axis**. Note that this angle is always in the range $`0^o \le \alpha \le 90^o`$.
+
+The CAST simply determines the positive/negatie signs of the result of a trig function of the related angle.
+
+<img src="https://mathonline.wdfiles.com/local--files/cast-rule/Screen%20Shot%202013-11-23%20at%203.45.11%20PM.png" width="500">
+
+Simple evaluate the related angle with the respective trigonmetery function, and add a negative sign according to the picture above.
+
+## Solving Trigonmetric Equations
+
+Just a few simple steps.
+
+1. Simplifiy the expression to make all the trig functions on one side, and the constants on the other. Makes sure **not** to divide or omit trig functiosn involving the variable as you might be omitting solutions. 
+2. Factor and simplify the expression, and state **ALL** possible solutions using `Co-terminal angles`.
+3. Profit!
+
+## Degrees and Radians
+
+A few formulas:
+
+To convert degrees to radians, multiply the degrees by $`\dfrac{\pi}{180^o}`$.
+
+To convert radians to degrees, multiply the radians by $`\dfrac{180^o}{\pi}`$
+
+To find the arc length ($`s`$) of the circle described by the angle and radius (or commonly known as **subtended** by the angle measure): $`s = r\theta`$, where $`\theta`$ is described in radians.
+
+In the absence of the degree symbol, the angle must be assumed to be in radians. It is also useful to know that $`\pi = 180^o`$ and $`2\pi = 360^o`$
+
+To find the RAA in terms of radians, follow the table below.
+
+|Quadrant|Quadrant 1 (All)|Quadrant 2 (Sin)|Quadrant 3 (tan)| Quadrant 4(cos)|
+|:-------|:---------------|:---------------|:---------------|:---------------|
+|Step to do to get $`\alpha`$|$`\alpha = \theta`$|$`\alpha = \pi - \theta`$|$`\alpha = \theta - \pi`$|$`\alpha = 2\pi - \theta`$|
+
+To find the area of a sector of a circle, the formula is as follows.
+
+$`\text{Sector Area } = (\text{Area of Circle})(\% \text{ Of Circle shaded in})`$
+
+$`A = (\pir^2)(\dfrac{\theta}{2\pi})`$
+$`A = \dfrac{1}{2}\theta r^2`$