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Unit 2: Quadratic Equations
- \(`\text{If } x \ge 0, x \in \mathbb{R}, \sqrt{x} \times \sqrt{x} = x`\)
Multiplication Of Radicals
- \(`\text{If } a, b \ge 0, \text{ and } a, b, \in \mathbb{R}, \text{ then } \sqrt{a} \times \sqrt{b} = \sqrt{ab}`\)
- There are two types of radical term,
- An entire radical is in the form \(`\sqrt{n}`\), where \(`n`\) is the radicand.
- A mixed radical is in the from \(`a\sqrt{b}`\), where \(`a`\) is the rational factor and \(`b`\) is the irrational factor.
Division Of Radicals
- \(`\text{If } a \ge 0, b \gt 0, \text{ and } a, b, \in \mathbb{R}, \text{ then } \dfrac{\sqrt{a}}{\sqrt{b}} = \sqrt{\dfrac{a}{b}}`\)
RULES!
\(`(\sqrt{x})^2 = x, x \gt 0`\), remember, \(`n`\) must be positive inorder for this equation to be true
\(`\sqrt{x^2} = |x|`\)
You can subtract like terms only if they the radicals have the same irrational factor. Eg \(`2 \sqrt{7} + 5 \sqrt{7} = 7 \sqrt{7}`\)
Rationalizing Denominator
Its not proper to leave radicals in the denominator, so we can multiply the denominator by it self, inorder to get rid of the radical.
Eg \(`\dfrac{\sqrt{7}}{\sqrt{3}} = \dfrac{\sqrt{7}}{\sqrt{3}} \times \dfrac{\sqrt{3}}{\sqrt{3}} = \dfrac{\sqrt{21}}{3}`\)
Although sometimes, if there is 2 terms in the denominator, we can multiply it by its conjugate. Recall difference of squares, \(`(a + b) \text{ and } (a-b)`\) are conjugates of one another.
Then, the denominator becames a difference of squares, and we got rid of the radical.
Eg \(`\dfrac{1+\sqrt{3}}{1-\sqrt{3}} \times \dfrac{1+\sqrt{3}}{1+\sqrt{3}} = \dfrac{(1+\sqrt{3})^2}{1-3} = \dfrac{1+2\sqrt{3}+3}{-2} = -4-\sqrt{3}`\)
Introduction To Quadratic Equation
- The standard form of a quadraic is \(`ax^2 + bx + c = 0`\), where \(`a`\) is the quadratic coefficient, \(`b`\) is the linear coefficient, and \(`c`\) is the constant coefficient.
- You can solve a quadratic by factoring/decomposition, then applying the Zero Factor Principle, and solve for \(`x`\). The Zero Factor Principle is if \(`A \times B = 0`\), then either \(`A = 0`\) or \(`B = 0`\).
Completing The Square
- This process is simply trying to create a perfect trinomial, while still balancing the equation/making the equation true
- The Standard form of a quadratic function \(`y = ax^2+bx+c`\) can be rearranged to Vertex form, \(`y = a(x-h)^2 + k`\) through completing the square, the Vertex \(`(h, k)`\) can be eaisly read from this form.
Steps To Complete The Square
- Factor out the \(`a`\) coefficient from the first 2 terms. Make sure to put brackets around them.
- Add and subtract within the brackets \(`(\dfrac{b}{2a})^2`\)
- Remove the bracket from step 1 by applying distrubutive property (multiplying \(`a`\)/the quadratic coefficient)
- Factor the perfect trinomial that was created, and combine like terms.
Solving Quadratic Equations By Completing The Square
- First complete the square of the quadratic equation/function.
- Move the constant terms to the other side.
- Square both sides.
- Isolate \(`x`\)
Quadratic Formula
x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\
\text{Where } ax^2+ bx + c = 0, a =\not 0, \text{ and } x \text{ are the roots of that quadratic equation}
- The formula is derived from completing the square.
- The sums of the roots is simply \(`\dfrac{-b}{a}`\), or \(`X_1 + X_2 = \dfrac{-b}{a}`\)
- The products of the roots, is simply \(`\dfrac{c}{a}`\), or \(`(X_1)(X_2) = \dfrac{c}{a}`\)
- The Axis of Symmetry is at \(`\dfrac{-b}{2a}`\)
Discriminant
- \(`D =b^2 - 4ac`\), this is also part of the quadratic formula!
- If \(`D > 0`\), the quadratic equation has 2 distinct real roots
- If \(`D = 0`\), the quadratic equation has 1 distinct real root or 2 equal real roots
- If \(`D < 0`\), the quadratic equation has no real roots
Two distinct real roots | One real root | No real roots |
---|---|---|
\(`b^2-4ac>0`\) | \(`b^2-4ac=0`\) | \(`b^2-4ac<0`\) |
Complex Numbers
- \(`i = \sqrt{-1}`\). This equation has no solution in the set of real numbers
- An expression in the from \(`a + bi`\), called the rectangular from, where \(`a`\) and \(`b`\) are real numbers, and \(`i`\) is a complex number.
- The set of complex numbers includes the real numbers since any real number \(`x`\) can be written as \(`x + i(0)`\).
- \(`a+bi`\) and \(`a-bi`\) are conjugates(same term with opposite signs).
- Complex roots of a quadratic quation occurs in conjugate pairs, recall discriminant, if its less than 0, there are 2 complex roots that are conjugates (\(`a \pm bi`\))
Complex Number | Equivalent |
---|---|
\(`i`\) | \(`\sqrt{-1}`\) |
\(`i^2`\) | \(`-1`\) |
\(`i^3`\) | \(`-\sqrt{-1}`\) or \(`-i`\) |
\(`i^4`\) | \(`1`\) |
Number Systems
- Natural Numbers \(`\mathbb{N} = \{1,2,3, \cdots\}`\)
- Whole Numbers \(`\mathbb{W} = \{0, 1, 2, 3\cdots\}`\)
- Integers \(`(\mathbb{I}`\) or \(`\mathbb{Z}) = \{\cdots, -2, -1, 0,1,2, \cdots\}`\)
- Rational numbers \(`(\mathbb{Q}) = \{\frac{a}{b}, a, b, \in \mathbb{I}, b =\not 0\}`\)
- Irrational Numbers \(`(\mathbb{Q} \prime)`\): any real number that cannot be written as \(`\frac{a}{b}, a, b, \in \mathbb{I}, b =\not 0`\)
- Real Numbers \(`(\mathbb{R})`\): the set of \(`\mathbb{Q} \cup \mathbb{Q} \prime`\)
- Complex Numbers \(`\mathbb{C}`\): any number that can be expressed in the form \(`a+ib`\) (includes the set of real numbers)
Radical Equations
Extraneous Sol
\(`\rightarrow`\) \(`LS =\not RS`\)Inadmissable Sol
\(`\rightarrow`\) Solutions you reject due to problem statement, eg negative length.Extraneous values
occur because squaring both sides of an equation is not a reversible step.- Make sure to check your work after working with radical equations, since squaring both sides is not a reversible step. Thus equations must be verified by pluging it back into the equation.
- Radical Equations are called that because the variable occurs under a radical sign. We rationalize the radical variable before continuing to slve the equation.