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phys: clarify kinematic equations

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eggy 2020-10-05 11:41:02 -04:00
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docs/sph3u7.md
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@ -299,11 +299,11 @@ The area below an acceleration-time graph at a given time is equal to the change
<img src="/resources/images/constant-acceleration.png" width=700>(Source: Kognity)</img>
- $s=$ change in displacement during time interval $t$ (i.e., from $t=0$ to $t$)
- $u=$ initial velocity at time $t=0$
- $v=$ final velocity at time $t$
- $s=$ change in displacement during time interval $t$ ($\Delta d$)
- $u=$ initial velocity ($v_1$)
- $v=$ final velocity ($v_2$)
- $a=$ constant acceleration
- $t=$ time elapsed since $t=0$
- $t=$ time elapsed ($\Delta t$)
By the formula of the gradient and the formula for the area underneath an acceleration time graph, the following formulas can be derived and are in the data booklet: