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Update Unit 1: Analytical Geometry.md

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James Su 2019-12-30 23:08:23 +00:00
parent a0225d195c
commit 580a93e0e4
1 changed files with 2 additions and 2 deletions
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Grade 10/Math/MPM2DZ/Math Oral Presentation Questions/Unit 1: Analytical Geometry.md
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@ -77,7 +77,7 @@ midpoint = $` (\dfrac{\sqrt{72} + \sqrt{32}}{2}, \dfrac{-\sqrt{12} - \sqrt{48}}{
$` = ( \dfrac{6\sqrt{2} + 4\sqrt{2}}{2}, \dfrac{-2\sqrt{3}, -4\sqrt{3}}{2}) `$
$` = 3\sqrt{2} + 2\sqrt{2}, -\sqrt{3 - 2\sqrt{3}`$
$` = 3\sqrt{2} + 2\sqrt{2}, -\sqrt{3} - 2\sqrt{3}`$
$` = (5\sqrt{2}, -3\sqrt{3})`$
@ -197,7 +197,7 @@ Let $`(x, y)`$ be the center of the circle, and $`r`$ be the radius of the circl
Sub $`(1)`$ into $`(2)`$
$`x^2 + 8x + 16 + y^2 - 16y + 64 = x^2 - 10x + 25 + y^2 -2y + 1`$
$`x^2 - 8x + 16 + y^2 - 16y + 64 = x^2 - 10x + 25 + y^2 -2y + 1`$
$`-8x -16y + 80 = -10x - 2y + 26`$